HomeWorldZelensky called on Georgia...

Zelensky called on Georgia to release Saakashvili for treatment

Photo: Office of the President

Saakashvili is in prison based on Georgian court verdicts and trials in 2018 on charges that have been ongoing since 2014.

President Volodymyr Zelensky called on Georgia to release Mikheil Saakashvili for medical treatment abroad. On Monday, December 19, he said in an evening speech.

“Perhaps everyone will see the state of Mikheil Saakashvili, the state of his health. Therefore, I appeal to the Georgian authorities: mercy should be shown. suits Georgia,” said Zelensky.

At the same time, he offered to transfer Saakashvili to any hospital in Ukraine, another European state or the United States.

“It’s time to take this good step,” Zelensky said.

Saakashvili led Georgia from 2008-2013. After losing the next election in 2013, he left the country. In the fall of 2021, Mikhail Saakashvili, a citizen of Ukraine since May 2015, decided to return to his homeland after a long absence, despite a sentence in absentia. On October 1, 2021, immediately after his arrival in Georgia, Saakashavili was detained.

It should be noted that heavy metals were found in the blood of the former President of Georgia Mikheil Saakashvili, the deterioration of his health may be due to poisoning.

It will be remembered that on December 14, Saakashvili announced a new hunger strike. According to the politician, he was denied the right to attend his own trial via video link.

news Correspondent.net on Telegram. Subscribe to our channel Athletistic

Source: korrespondent

- A word from our sponsors -

Most Popular

LEAVE A REPLY

Please enter your comment!
Please enter your name here

More from Author

- A word from our sponsors -

Read Now